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Topic started 13 years ago by LikeASong in Your Blue Room. Since then 17,807 posts have been made by 182 users.

LikeASong

13 years

Then, start doing it. It would free you (and us) from a lot of your rants here Nah, just messing with you. I'm also an active user on some other forums (U2 related and not), it's just that I'm not a crew member on any of them Nothing wrong with posting here as long as your posts make a minimum of sense
Mr_Trek

13 years

Originally posted by LikeASong:Then, start doing it. It would free you (and us) from a lot of your rants here Nah, just messing with you. I'm also an active user on some other forums (U2 related and not), it's just that I'm not a crew member on any of them Nothing wrong with posting here as long as your posts make a minimum of sense

I am the walrus.
Mr_Trek

13 years

So..... CHEMISTRY
LikeASong

13 years

National exam? That's sweeeeet
iTim

13 years

Or...Mathematics!
Mr_Trek

13 years

Originally posted by LikeASong:National exam? That's sweeeeet

Not exactly... anything from the last four years could come up.
LikeASong

13 years

Originally posted by Mr_Trek:[..]

Not exactly... anything from the last four years could come up.

And could you tell what are you exactly doing on U2start instead of studying like a bastard?
Mr_Trek

13 years

Originally posted by LikeASong:[..]

And could you tell what are you exactly doing on U2start instead of studying like a bastard?

U2start is more fun than studying.
LikeASong

13 years

Originally posted by Mr_Trek:[..]

U2start is more fun than studying.

Yes, but I sincerely doubt that tomorrow they ask you:

Calculate the volume of a 0.520 M sodium hydroxide solution that is neutralized by the addition of 100 mL of a 0.203 M U2startic acid solution.
Mr_Trek

13 years

Originally posted by LikeASong:[..]

Yes, but I sincerely doubt that tomorrow they ask you:

Calculate the volume of a 0.520 M sodium hydroxide solution that is neutralized by the addition of 100 mL of a 0.203 M U2startic acid solution.

Well, I think the exam is gonna be a lot more basic than that.
LikeASong

13 years

That would be pretty easy, even if the U2startic acid existed

You only have to calculate how many moles of U2startic there are in 100 mL of solution (100 mL = 0'1 L ==> if the solution is 0'203 M, there are 0'203 moles in one litre, and 0'0203 moles in 0'1 litres).
And then, calcule how much NaOH solution gets neutralized by that moles of acid (asking "hoy much solution of 0'520M NaOH contains 0'0203 moles of NaOH?").
Assuming a density of 1g/mL for the NaOH solution (not faithful, but...) and a 1:1 stoichiometry (depending on the valence of the supposed U2startous element hahaha), it's a pretty easy calculus:
0'0203 moles = 0'520M · X_unknown volume_ L (careful here, L and not mL) ==> the volume of NaOH solution that gets neutralized by 100 mL of U2startic acid is of 39 mL
Mr_Trek

13 years

Cool story bro.

We haven't gotten to that level yet. I hope I'll sooner rather than later.

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